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Ticket: 5c1709568018c arsetpopeye
17 Dec 09:26
Diketahui f(x) = 3x² - 2x + ?∫² f(x) dx. Jika f?¹(-3) = a maka nilai a = ...
A. -1/3
B. -2/3
C. -1
D. -2
E. -3
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arsetpopeye
17 Dec 09:29

f(x) = 3x2 - 2x + 02 f(x) dx. Jika f -1(-3) = a, a = ...

m43p05
24 Dec 22:13

misalkan: 02 f(x) dx = p (integral tentu hasilnya konstanta)

f(x) = 3x- 2x + p

\int_{0}^{2}f(x)dx=\int_{0}^{2}(3x^{2}-2x+p)dx=p

\left [x^3-x^2+px \right ]^2_0=p

4+2p=p

p=-4

jadi f(x) = 3x2 - 2x - 4

sifat invers f - 1(y) = x ==> f(x) = y

f - 1( - 3) = a ==> f(a) = - 3 

3a2 - 2a - 4 = - 3

3a2 - 2a - 1 = 0 

(3a + 1)(a - 1) = 0 

a = - 1/3 atau a = 1 

mohon dikoreksi, semoga bermanfaat...